JEE Main 2022 · 26 July · morning · Single correct · +4 / −1
A charge particle is moving in a uniform magnetic field (2 î+3 ĵ) T. If it has an acceleration of (α î-4 ĵ) m / s², then the value of α will be :
- (a) 3
- (b) 6
- (c) 12
- (d) 2
Answer and solution
Answer (b) 6
Solution
Physics sir · 3 steps
Magnetic force is always perpendicular to B, so set the dot product of a and B to zero.
- Direction of force. The magnetic force is F⃗ = q v⃗ × B⃗. A cross product is always perpendicular to both vectors in it, so F⃗ is perpendicular to B⃗.
- Same for acceleration. Acceleration is a⃗ = F⃗/m, so it points along F⃗. That means a⃗ is also perpendicular to B⃗, and their dot product must be zero.
a⃗·B⃗ = (α)(2) + (-4)(3) = 2α - 12 = 0
- So. 2α = 12, which gives α = 6. The answer is (b).
The idea to keep. A magnetic field can only push sideways. Whenever B is given along with the force or acceleration of a charge, set their dot product to zero.
Answer from the NTA final answer key. Solution by PrepWiser.