JEE Main 2021 · 17 March · evening · Single correct · +4 / −1

One of the by-products formed during the recovery of NH₃ from Solvay process is :

  1. (a) Ca(OH)₂
  2. (b) NH₄Cl
  3. (c) NaHCO₃
  4. (d) CaCl₂
Answer and solution

Answer (d) CaCl₂

Solution

Chemistry ma’am · 3 steps

Ammonia is recovered by heating NH₄Cl with lime, and the calcium is left behind as CaCl₂.

  1. Main reaction. Brine is saturated with NH₃ and CO₂ is passed through it. NaHCO₃ precipitates because it is only sparingly soluble, and NH₄Cl stays in solution: NaCl + NH₃ + CO₂ + H₂O → NaHCO₃ + NH₄Cl.
  2. Recovering ammonia. NH₃ is too costly to throw away, so the NH₄Cl solution is heated with slaked lime. The lime comes from heating limestone, CaCO₃ → CaO + CO₂, followed by CaO + H₂O → Ca(OH)₂.

    2NH₄Cl + Ca(OH)₂ → 2NH₃ ↑ + CaCl₂ + 2H₂O

  3. So. NH₃ goes back into the process, and CaCl₂ is the by-product of this step. The answer is (d).

The idea to keep. In the Solvay process, CO₂ and NH₃ are both recycled. The only real waste is CaCl₂, formed when NH₄Cl is treated with Ca(OH)₂.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 130 times in JEE Main since 2020. This question is from 2021.