JEE Main 2021 · 25 July · evening · Single correct · +4 / −1
Two ions having same mass have charges in the ratio 1 : 2. They are projected normally in a uniform magnetic field with their speeds in the ratio 2 : 3. The ratio of the radii of their circular trajectories is :
- (a) 1 : 4
- (b) 4 : 3
- (c) 3 : 1
- (d) 2 : 3
Answer and solution
Answer (b) 4 : 3
Solution
Physics sir · 3 steps
Same mass, so the radius depends only on v over q: put in both ratios and divide.
- Force gives radius. For an ion moving perpendicular to the field, the magnetic force qvB supplies the centripetal force mv²/r. Setting them equal gives r = mv/qB.
- Take the ratio. Both ions have the same m and are in the same B, so these cancel. The radius is proportional to speed and inversely proportional to charge.
r₁/r₂ = v₁/v₂ × q₂/q₁ = 2/3 × 2/1 = 4/3
- So. The radii are in the ratio 4 : 3, which is option (b).
The idea to keep. In a magnetic field, r = mv/qB. Charge sits in the denominator, so flip the charge ratio before you multiply it with the other ratios.
Answer from the NTA final answer key. Solution by PrepWiser.