JEE Main 2020 · 4 September · evening · Single correct · +4 / −1

An alkaline earth metal ‘M’ readily forms water soluble sulphate and water insoluble hydroxide. Its oxide MO is very stable to heat and does not have rock-salt structure. M is :

  1. (a) Ca
  2. (b) Mg
  3. (c) Sr
  4. (d) Be
Answer and solution

Answer (d) Be

Solution

Chemistry ma’am · 3 steps

The first two clues still leave Mg and Be; only the oxide's crystal structure picks Be.

  1. Sulphate and hydroxide. Down group 2, sulphates become less soluble and hydroxides become more soluble. A soluble sulphate with an insoluble hydroxide points to the top of the group, so the choice is Be or Mg.
    MetalMSO₄ in waterM(OH)₂ in waterStructure of MO
    Besolubleinsolublewurtzite (4:4), not rock salt
    Mgsolubleinsolublerock salt (6:6)
    Casparingly solublesparingly solublerock salt (6:6)
    Srinsolublefairly solublerock salt (6:6)
  2. Why BeO differs. Be²⁺ is so small that only four O²⁻ ions fit around it, so BeO takes the wurtzite structure. MgO, CaO and SrO all have the six-coordinate rock-salt structure. BeO is also very stable to heat, with a melting point above 2500 °C.
  3. So. Only beryllium fits every clue, so M is Be, option (d).

The idea to keep. Group 2 trends: sulphate solubility falls and hydroxide solubility rises down the group. When Be and Mg both fit, look for Be's small-ion anomaly, like the wurtzite structure of BeO.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 130 times in JEE Main since 2020. This question is from 2020.