JEE Main 2024 · 9 April · evening · Single correct · +4 / −1
lim x → 0 (e-(1+2 x)^(1/(2 x)))/x is equal to
- (a) -2/e
- (b) e-e²
- (c) 0
- (d) e
Answer and solution
Answer (d) e
Solution
Maths sir · 3 steps
The bracket tends to e, so expand it to first order in x and see what survives after dividing by x.
- Take the log. Let y = (1+2x)^(1/2x). Then ln y = ln(1+2x)/2x. Use ln(1+t) = t - t²/2 + … with t = 2x, which gives ln y = 1 - x + ….
- Back to y. So y = e^(1 - x + …) = e · e^(-x + …). Since e⁻ˣ ≈ 1 - x for small x, this gives y ≈ e(1 - x) to first order.
(e - (1+2x)^(1/2x))/x ≈ (e - e(1-x))/x = ex/x = e
- So. The terms we dropped are of order x², so they vanish after dividing by x. The limit equals e, which is option (d).
The idea to keep. When (1+t)^(1/t) sits next to e in a 0/0 form, use (1+t)^(1/t) ≈ e(1 - t/2). Keep the first-order term, because it is the whole answer.
Answer from the NTA final answer key. Solution by PrepWiser.