JEE Main 2026 · 28 January · evening · Single correct · +4 / −1
Identify the correct statements :
A. Electrostatic field lines form closed loops.
B. The electric field lines point radially outward when charge is greater than zero.
C. The Gauss - Law is valid only for inverse-square force.
D. The work done in moving a charged particle in a static electric field around a closed path is zero.
E. The motion of a particle under Coulomb's force must take place in a plane.
Choose the correct answer from the options given below :
- (a) A, C, E Only
- (b) A, B, D, E Only
- (c) B, C, D, E Only
- (d) A, B, C, D Only
Answer and solution
Answer (c) B, C, D, E Only
Solution
Physics sir · 2 steps
Strike out statement A first: static field lines never close, and that alone rules out three options.
- Why A fails. Electrostatic field lines start on positive charges and end on negative charges, or go off to infinity. A closed loop would mean ∮ E⃗ · dl⃗ ≠ 0, and that cannot happen for a static field.
∮ E⃗_(static) · dl⃗ = 0
Statement True or false Reason A False Lines begin and end on charges. Only induced (changing-flux) fields form closed loops. B True For a positive point charge, E⃗ points away from the charge along every radius. C True Flux through a closed surface is independent of its size only because E ∝ 1/r² cancels the r² growth of area. D True The electrostatic force is conservative, so the work around any closed path is zero. E True Coulomb force is a central force. It exerts no torque about the charge, so L⃗ is conserved and the motion stays in one plane. - So. B, C, D and E are correct and A is wrong. That matches option (c).
The idea to keep. Static field lines run from plus to minus and never close, since ∮ E⃗ · dl⃗ = 0. In statement lists, find the false one first and strike every option containing it.
Answer from the NTA final answer key. Solution by PrepWiser.