JEE Main 2022 · 29 July · morning · Single correct · +4 / −1
Let a⃗=3 î+ĵ and b⃗=î+2 ĵ+k̂. Let c⃗ be a vector satisfying a⃗ ×(b⃗ × c⃗)=b⃗+λ c⃗. If b⃗ and c⃗ are non-parallel, then the value of λ is :
- (a) -5
- (b) 5
- (c) 1
- (d) -1
Answer and solution
Answer (a) -5
Solution
Maths sir · 4 steps
Expand the triple product, then match the coefficients of b and c on both sides.
- Expand. Use the BAC minus CAB rule on the left side.
a⃗ × (b⃗ × c⃗) = (a⃗·c⃗) b⃗ - (a⃗·b⃗) c⃗ = b⃗ + λc⃗
- Compare coefficients. Since b⃗ and c⃗ are non-parallel, they are linearly independent, so the coefficients on each side must match. This gives a⃗·c⃗ = 1 and λ = -(a⃗·b⃗).
- Find the dot product. a⃗·b⃗ = (3)(1) + (1)(2) + (0)(1) = 5.
- So. λ = -5, which is option (a).
The idea to keep. When a triple product equals a combination of two non-parallel vectors, expand it as (a⃗·c⃗)b⃗ - (a⃗·b⃗)c⃗ and compare coefficients. Watch the minus sign.
Answer from the NTA final answer key. Solution by PrepWiser.