JEE Main 2021 · 25 February · evening · Numerical answer · +4 / −0
Two particles having masses 4 g and 16 g respectively are moving with equal kinetic energies. The ratio of the magnitudes of their linear momentum is n : 2. The value of n will be ___________.
Answer and solution
Answer 1
Solution
Physics sir · 3 steps
Equal kinetic energy means momentum goes as the square root of mass, so the lighter one has less.
- Link p and K. Kinetic energy is K = p²/2m, so momentum is p = √2mK.
p₁/p₂ = √(m₁/m₂) (K₁ = K₂)
- Put in numbers. With m₁ = 4 g and m₂ = 16 g, p₁/p₂ = √(4/16) = 1/2.
- So. The ratio is 1 : 2. Matching it with n : 2 gives n = 1.
The common slip: 4. Writing p ∝ 1/√m flips the ratio to 2 : 1, which gives n = 4. Speed goes as 1/√m, but momentum goes as √m.
The idea to keep. Whenever kinetic energies are equal, use p = √2mK. Momentum grows as √m, so the heavier body carries more momentum even though it moves slower.
Answer from the NTA final answer key. Solution by PrepWiser.