The orbital having two radial as well as two angular nodes is :

Solution

Chemistry ma’am · 3 steps

Two angular nodes fixes l = 2, a d orbital; then use n - l - 1 to find which d has two radial nodes.

1. Two node formulas. The number of angular nodes equals l. The number of radial nodes equals n - l - 1. Together they add up to n - 1 nodes in all.
2. Angular nodes first. Two angular nodes means l = 2, so the orbital must be a d orbital. Then two radial nodes means n - 2 - 1 = 2, which gives n = 5.

   Orbital	n, l	Angular nodes (l)	Radial nodes (n - l - 1)
   3p	3, 1	1	3 - 1 - 1 = 1
   5d	5, 2	2	5 - 2 - 1 = 2
   4d	4, 2	2	4 - 2 - 1 = 1
   4f	4, 3	3	4 - 3 - 1 = 0

3. So. Only 5d has two radial nodes and two angular nodes, so the answer is (b).

The idea to keep. Angular nodes come from l alone, and radial nodes are n - l - 1. Read off l from the angular nodes first, then use the radial count to find n.

Answer from the NTA final answer key. Solution by PrepWiser.