JEE Main 2023 · 12 April · morning · Single correct · +4 / −1
In an n-p-n common emitter (CE) transistor the collector current changes from 5 mA to 16 mA for the change in base current from 100 μ A and 200 μ A, respectively. The current gain of transistor is __________.
- (a) 210
- (b) 0.9
- (c) 9
- (d) 110
Answer and solution
Answer (d) 110
Solution
Physics sir · 3 steps
Current gain here means the ratio of the changes: change in collector current over change in base current.
- Which gain. In the common emitter setup, the base current is the input and the collector current is the output. The current gain β is how much the collector current changes for a given change in the base current.
β = (Δ I_C)/(Δ I_B)
- Find the changes. Δ I_C = 16 - 5 = 11 mA. Δ I_B = 200 - 100 = 100 μA = 0.1 mA.
- So. β = (11 mA)/(0.1 mA) = 110, which is option (d).
The idea to keep. When a question gives two pairs of readings, take differences before dividing. Also put both currents in the same unit, since μA and mA differ by a factor of 1000.
Answer from the NTA final answer key. Solution by PrepWiser.