JEE Main 2025 · 29 January · evening · Single correct · +4 / −1

The difference of temperature in a material can convert heat energy into electrical energy. To harvest the heat energy, the material should have

  1. (a) low thermal conductivity and high electrical conductivity
  2. (b) low thermal conductivity and low electrical conductivity
  3. (c) high thermal conductivity and high electrical conductivity
  4. (d) high thermal conductivity and low electrical conductivity
Answer and solution

Answer (a) low thermal conductivity and high electrical conductivity

Solution

Physics sir · 4 steps

Keep the hot end hot and let the charges flow: block the heat, but pass the current.

  1. What drives it. This is the thermoelectric (Seebeck) effect. A temperature difference across the material pushes charge carriers from the hot side to the cold side, and that creates a voltage. No temperature difference means no voltage.
  2. Low thermal conductivity. If heat conducts through the material easily, the hot and cold ends quickly reach the same temperature. A poor heat conductor keeps that temperature difference alive, so the voltage keeps being produced.
  3. High electrical conductivity. The voltage is only useful if it can drive a current. A good electrical conductor has low resistance, so less of the harvested energy is wasted as Joule heating I²R inside the material.

    ZT = (S² σ T)/κ

  4. So. The figure of merit ZT of a thermoelectric material grows with electrical conductivity σ and falls with thermal conductivity κ. The material should have low thermal conductivity and high electrical conductivity, option (a).

The idea to keep. In a thermoelectric material the temperature difference is the fuel. Make it a poor conductor of heat so the difference survives, and a good conductor of electricity so the current flows with little loss.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Heat Transfer

Asked about 30 times in JEE Main since 2020. This question is from 2025.