JEE Main 2020 · 9 January · morning · Numerical answer · +4 / −0

The coefficient of x⁴ is the expansion of (1 + x + x²)¹⁰ is _____.

Answer and solution

Answer 615

Solution

Maths sir · 3 steps

Pick a term from each of the 10 brackets and count every way the powers add up to 4.

  1. Set up choices. Each of the 10 brackets gives 1, x or x². Say p brackets give 1, q give x and r give x². Then p + q + r = 10 and the power is q + 2r = 4.

    Number of ways = 10!/(p! q! r!)

    r (brackets giving x²)q (brackets giving x)p (brackets giving 1)Ways
    04610!/(6! 4!) = 210
    12710!/(7! 2! 1!) = 360
    20810!/(8! 2!) = 45
  2. Why the middle row. With r = 1, q = 2 you choose 1 bracket for x² in 10 ways, then 2 of the remaining 9 for x in 36 ways. That gives 10 × 36 = 360, the biggest share.
  3. So. The coefficient of x⁴ is 210 + 360 + 45 = 615.

The common slip: 255. Leaving out the mixed case with one x² and two x gives 210 + 45 = 255, not 615.

The idea to keep. For a trinomial raised to a power, list every split of the exponent with q + 2r = n and add the multinomial counts N!/(p! q! r!). Mixed cases usually carry the most weight.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Binomial Theorem

Asked about 200 times in JEE Main since 2020. This question is from 2020.