JEE Main 2023 · 13 April · morning · Single correct · +4 / −1

Which graph represents the difference between total energy and potential energy of a particle executing SHM vs it's distance from mean position ?

  1. (a)
    Option (a)
  2. (b)
    Option (b)
  3. (c)
    Option (c)
  4. (d)
    Option (d)
Answer and solution

Answer (a)

Solution

Physics sir · 3 steps

Total energy minus potential energy is just kinetic energy, so sketch K against x.

  1. Name the difference. In SHM the total energy E = 1/2kA² stays constant, and U = 1/2kx². Their difference is the kinetic energy.

    E - U = 1/2kA² - 1/2kx² = 1/2k(A² - x²)

  2. Read the shape. This depends on x², so the graph is the same at x and -x. It is largest, 1/2kA², at x = 0 and falls to zero at x = ± A. It is a smooth curve opening downward with a rounded top, not straight lines.
  3. So. The graph must be a smooth, symmetric hump with its peak at the mean position and zero at both extremes. That is graph (a).

The idea to keep. In SHM, E - U is always the kinetic energy 1/2k(A² - x²). Kinetic energy is greatest at the mean position, zero at the extremes, and depends only on x², so its graph is symmetric.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Simple Harmonic Motion

Asked about 130 times in JEE Main since 2020. This question is from 2023.