JEE Main 2023 · 11 April · evening · Single correct · +4 / −1
Given below are two statements :
Statement I : In the metallurgy process, sulphide ore is converted to oxide before reduction.
Statement II : Oxide ores in general are easier to reduce.
In the light of the above statements, choose the most appropriate answer from the options given below:
- (a) Both Statement I and Statement II are correct
- (b) Both Statement I and Statement II are incorrect
- (c) Statement I is correct but Statement II is incorrect
- (d) Statement I is incorrect but Statement II is correct
Answer and solution
Answer (a) Both Statement I and Statement II are correct
Solution
Chemistry ma’am · 4 steps
Carbon can grab oxygen easily but not sulphur, so we roast the sulphide to an oxide first.
- Statement I. Sulphide ores are roasted, which means heating them strongly in air. This turns the sulphide into an oxide and releases SO₂. Reduction happens only after this step, so Statement I is correct.
2ZnS + 3O₂ →(Δ) 2ZnO + 2SO₂ ZnO + C →(Δ) Zn + CO
- Statement II. To reduce a sulphide with carbon, the carbon would have to form CS₂. That compound has a positive Δ_f G°, so the reaction is not feasible. To reduce an oxide, carbon forms CO or CO₂, which have large negative Δ_f G°. That makes the overall Δ G negative at high temperature, so oxides are easier to reduce and Statement II is correct.
- Link between them. Statement II is the reason behind Statement I. Because oxides are easier to reduce, sulphides are first converted into oxides.
- So. Both statements are correct, which is option (a).
The idea to keep. Reduction works when the reducing agent forms a very stable product. CO and CO₂ are very stable, but CS₂ is not, so oxides reduce easily while sulphides must be roasted first.
Answer from the NTA final answer key. Solution by PrepWiser.