JEE Main 2025 · 22 January · morning · Single correct · +4 / −1

A line charge of length a/2 is kept at the center of an edge B C of a cube ABCDEFGH having edge length ' a ' as shown in the figure. If the density of line charge is λ C per unit length, then the total electric flux through all the faces of the cube will be ___________ . (Take, ε₀ as the free space permittivity)

JEE Main PYQ figure
  1. (a) (λ a)/(2 ε₀)
  2. (b) (λ a)/(8 ε₀)
  3. (c) (λ a)/(4 ε₀)
  4. (d) (λ a)/(16 ε₀)
Answer and solution

Answer (b) (λ a)/(8 ε₀)

Solution

Physics sir · 3 steps

The charge sits on an edge, and an edge is shared by four cubes, so this cube gets only a quarter of the flux.

  1. Total charge. The line charge has length a/2 and density λ, so it carries q = (λ a)/2. If it were fully enclosed, Gauss's law would give a flux of q/ε₀.
  2. Edge sharing. The charge lies along edge BC, not inside the cube. Imagine identical cubes stacked around that edge: exactly 4 cubes meet at it and together enclose the charge completely. By symmetry, each cube receives an equal share of the flux.

    φ = 1/4×q/ε₀ = 1/4×(λ a)/2ε₀ = (λ a)/8ε₀

  3. So. The total flux through all the faces of the cube is (λ a)/8ε₀, which is option (b).

The idea to keep. For a charge on the boundary of a cube, build the full set of cubes around it. Inside gives the full q/ε₀, on a face half, on an edge a quarter, at a corner one-eighth.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Electrostatics I — Charges, Field & Gauss's Law

Asked about 150 times in JEE Main since 2020. This question is from 2025.