JEE Main 2020 · 5 September · morning · Single correct · +4 / −1

If 2¹⁰ + 2⁹.3¹ + 2⁸ .3² +.....+ 2.3⁹ + 3¹⁰ = S - 2¹¹, then S is equal to :

  1. (a) 3¹¹/2 + 2¹⁰
  2. (b) 3¹¹ — 2¹²
  3. (c) 2.3¹¹
  4. (d) 3¹¹
Answer and solution

Answer (d) 3¹¹

Solution

Maths sir · 3 steps

Every term is 2ᵃ 3ᵇ with a + b = 10, so this is the factor of 3¹¹ - 2¹¹ in disguise.

  1. Spot the pattern. The powers of 2 fall from 10 to 0 while the powers of 3 rise from 0 to 10. That gives 11 terms, each one 3/2 times the one before it. So the sum is a GP with first term 2¹⁰ and ratio 3/2.

    2¹⁰·((3/2)¹¹-1)/(3/2-1) = 2¹¹(3¹¹/2¹¹-1) = 3¹¹-2¹¹

  2. Same via identity. This is the identity a¹¹-b¹¹ = (a-b)(a¹⁰+a⁹b+…+b¹⁰) with a = 3 and b = 2. Since a - b = 1, the bracket equals 3¹¹-2¹¹.
  3. So. S - 2¹¹ = 3¹¹ - 2¹¹. Add 2¹¹ to both sides to get S = 3¹¹, which is option (d).

The idea to keep. A sum like aⁿ⁻¹ + aⁿ⁻²b + … + bⁿ⁻¹ is always (aⁿ - bⁿ)/(a - b). Spot it and the whole sum collapses in one line.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Binomial Theorem

Asked about 200 times in JEE Main since 2020. This question is from 2020.