JEE Main 2021 · 18 March · morning · Single correct · +4 / −1
The number of integral values of m so that the abscissa of point of intersection of lines 3x + 4y = 9 and y = mx + 1 is also an integer, is :
- (a) 1
- (b) 2
- (c) 3
- (d) 0
Answer and solution
Answer (b) 2
Solution
Maths sir · 3 steps
Solve for x in terms of m, then ask which values of 3 + 4m can divide 5 exactly.
- Find the abscissa. Put y = mx + 1 into 3x + 4y = 9. This gives 3x + 4mx + 4 = 9, so x(3 + 4m) = 5.
x = 5/(3 + 4m)
- Integer condition. If m is an integer, 3 + 4m is an integer. Then x is an integer only when 3 + 4m divides 5, so 3 + 4m must be one of 1, -1, 5, -5.
3 + 4m m Integer m? x 1 -1/2 no 5 -1 -1 yes -5 5 1/2 no 1 -5 -2 yes -1 - So. Only m = -1 and m = -2 work, so there are 2 integral values of m.
The idea to keep. When a coordinate comes out as a fraction like k/expression, demanding an integer means the expression must be a divisor of k. List every divisor, negative ones too.
Answer from the NTA final answer key. Solution by PrepWiser.