JEE Main 2025 · 22 January · evening · Single correct · +4 / −1

Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : In Young's double slit experiment, the fringes produced by red light are closer as compared to those produced by blue light.
Reason (R) : The fringe width is directly proportional to the wavelength of light.
In the light of the above statements, choose the correct answer from the options given below :

  1. (a) (A) is true but (R) is false
  2. (b) Both (A) and (R) are true and (R) is the correct explanation of (A)
  3. (c) (A) is false but (R) is true
  4. (d) Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
Answer and solution

Answer (c) (A) is false but (R) is true

Solution

Physics sir · 3 steps

Fringe width grows with wavelength, and red has the longer wavelength, so red fringes are wider apart.

  1. Check the Reason. In Young's double slit experiment the fringe width is β = (λ D)/d. With the same D and d, β is directly proportional to λ, so (R) is true.

    β = (λ D)/d ⇒ β ∝ λ

  2. Compare the colours. Red light has a longer wavelength (about 700 nm) than blue light (about 450 nm). So red fringes are wider, that is, farther apart, not closer.
  3. So. (A) is false and (R) is true, which is option (c).

The idea to keep. In YDSE, β = λ D/d: longer wavelength means wider fringes. Remember the order VIBGYOR, where violet has the narrowest fringes and red the widest.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Wave Optics

Asked about 140 times in JEE Main since 2020. This question is from 2025.