Match List - I with List - II
Choose the most appropriate answer from the options given below :

Solution

Physics sir · 4 steps

Pin down B from F = qvB first; flux and permeability follow, and magnetization is A/m.

1. Magnetic induction. From F = qvB, B = F/qv. With q = AT and v = LT⁻¹, this gives [B] = MLT⁻²/(AT × LT⁻¹) = MT⁻²A⁻¹, which is (iii).
2. Flux and permeability. Flux is B times area, so [φ] = MT⁻²A⁻¹ × L² = ML²T⁻²A⁻¹, which is (i). From B = (μ₀ I)/(2π r), μ₀ = (2π Br)/I, so [μ₀] = MLT⁻²A⁻², which is (iv).
3. Magnetization. Magnetization is magnetic moment per unit volume. Magnetic moment is current times area, AL², so magnetization has dimensions AL²/L³ = M⁰L⁻¹A, which is (ii).

   Quantity	Built from	Dimensions	Match
   Magnetic induction B	F/(qv)	MT⁻²A⁻¹	(iii)
   Magnetic flux φ	B × area	ML²T⁻²A⁻¹	(i)
   Permeability μ₀	2π Br/I	MLT⁻²A⁻²	(iv)
   Magnetization	moment / volume	M⁰L⁻¹A	(ii)

4. So. The matching is (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii), which is option (d).

The idea to keep. Fix [B] = MT⁻²A⁻¹ from F = qvB once. Flux and μ₀ follow by multiplying or dividing by L or A. Magnetization and H share units of A/m, not tesla.

Answer from the NTA final answer key. Solution by PrepWiser.