JEE Main 2020 · 8 January · morning · Single correct · +4 / −1
Let y = y(x) be a solution of the differential equation,
√(1 - x²) dy/dx + √(1 - y²) = 0, |x| < 1.
If y( 1/2 ) = √3/2, then y( - 1/√2 ) is equal to :
- (a) - √3/2
- (b) None of those
- (c) 1/√2
- (d) -1/√2
Answer and solution
Answer (c) 1/√2
No written solution for this question yet.