JEE Main 2025 · 2 April · morning · Single correct · +4 / −1

The largest n ∈ N such that 3ⁿ divides 50 ! is :

  1. (a) 22
  2. (b) 20
  3. (c) 21
  4. (d) 23
Answer and solution

Answer (a) 22

Solution

Maths sir · 3 steps

Do not list 50 numbers; count how many are divisible by 3, then by 9, then by 27.

  1. Count the threes. The power of 3 in 50! is the total number of factors of 3 across 1, 2, …, 50. A multiple of 3 gives at least one, a multiple of 9 gives one more, and a multiple of 27 gives one more again.

    ⌊ 50/3 ⌋ + ⌊ 50/9 ⌋ + ⌊ 50/27 ⌋ + ⌊ 50/81 ⌋

  2. Each term. There are 16 multiples of 3, 5 multiples of 9 and 1 multiple of 27 (that is 27 itself). Since 81 > 50, every later term is 0.
  3. So. 16 + 5 + 1 = 22, so 3²² divides 50! but 3²³ does not. The answer is (a) 22.

The idea to keep. The power of a prime p in n! is ⌊ n/p ⌋ + ⌊ n/p² ⌋ + ⌊ n/p³ ⌋ + … Keep adding terms until pᵏ is bigger than n.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Binomial Theorem

Asked about 200 times in JEE Main since 2020. This question is from 2025.