JEE Main 2022 · 29 July · evening · Single correct · +4 / −1
Let the function f(x)={(log ₑ(1+5 x)-log ₑ(1+α x))/x, ; if x ≠ 0; 10, ; if x=0 be continuous at x=0 .
Then α is equal to
- (a) 10
- (b) -10
- (c) 5
- (d) -5
Answer and solution
Answer (d) -5
Solution
Maths sir · 3 steps
Split the log difference into two standard limits; each one just hands you its coefficient.
- Continuity condition. For f to be continuous at x = 0, the limit of f(x) as x → 0 must equal f(0) = 10.
- Standard limit. Use lim(x → 0) ln(1+kx)/x = k. Split the fraction into two such limits, one with k = 5 and one with k = α.
lim(x → 0)(ln(1+5x)/x - ln(1+α x)/x) = 5 - α
- So. Set 5 - α = 10, which gives α = -5. The answer is (d).
The idea to keep. Whenever you see ln(1+kx) divided by x near zero, read off k straight away. Then match the limit to the value given at the point.
Answer from the NTA final answer key. Solution by PrepWiser.