JEE Main 2024 · 31 January · morning · Numerical answer · +4 / −1

Two waves of intensity ratio 1: 9 cross each other at a point. The resultant intensities at that point, when (a) Waves are incoherent is I₁ (b) Waves are coherent is I₂ and differ in phase by 60°. If I₁/I₂=10/x then x= _________.

Answer and solution

Answer 13

Solution

Physics sir · 4 steps

Incoherent waves add intensities; coherent waves add amplitudes, which brings in an extra interference term.

  1. Set the intensities. Take the two intensities as I₀ and 9I₀, which matches the ratio 1:9.
  2. Incoherent case. With no fixed phase relation, the interference term averages to zero and the intensities add directly: I₁ = I₀ + 9I₀ = 10I₀.

    I₂ = Iₐ + I_b + 2√(Iₐ I_b)cos φ

  3. Coherent case. Here √(I₀ × 9I₀) = 3I₀ and cos 60° = 1/2. So I₂ = 10I₀ + 2 × 3I₀ × 1/2 = 13I₀.
  4. So. I₁/I₂ = 10I₀/13I₀ = 10/13, so x = 13.

The common slip: 16. Leaving out cos 60° makes the extra term 6I₀ and gives 16, not 13.

The idea to keep. Incoherent sources: add the intensities. Coherent sources: add 2√(Iₐ I_b)cos φ to that sum, and this term carries all the phase information.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Wave Optics

Asked about 140 times in JEE Main since 2020. This question is from 2024.