JEE Main 2021 · 27 July · evening · Single correct · +4 / −1

The addition of silica during the extraction of copper from its sulphide ore :-

  1. (a) converts copper sulphide into copper silicate
  2. (b) converts iron oxide into iron silicate
  3. (c) reduces copper sulphide into metallic copper
  4. (d) reduces the melting point of the reaction mixture
Answer and solution

Answer (b) converts iron oxide into iron silicate

Solution

Chemistry ma’am · 4 steps

Silica is a flux here: it grabs the iron oxide impurity and carries it away as slag.

  1. The impurity. Copper pyrites, CuFeS₂, carries a lot of iron. During roasting, iron sulphide is oxidised to iron oxide: 2FeS + 3O₂ → 2FeO + 2SO₂.
  2. Silica as flux. FeO is a basic oxide and silica is an acidic flux. In the blast furnace they combine to form ferrous silicate, the slag.

    FeO + SiO₂ → FeSiO₃ (slag)

  3. Slag floats off. The light, molten slag floats on top and is removed. What is left below is copper matte, mostly Cu₂S with a little FeS.
  4. So. Silica turns iron oxide into iron silicate, which is option (b). Copper stays as Cu₂S and is reduced later by self-reduction, not by silica.

The idea to keep. Match the flux to the impurity: an acidic flux like SiO₂ removes a basic impurity like FeO, and a basic flux like CaO removes an acidic one like SiO₂.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 80 times in JEE Main since 2020. This question is from 2021.