JEE Main 2025 · 28 January · evening · Single correct · +4 / −1
For bacterial growth in a cell culture, growth law is very similar to the law of radioactive decay. Which of the following graphs is most suitable to represent bacterial colony growth ?
Where N - Number of Bacteria at any time, N₀ - Initial number of Bacteria.
- (a)
- (b)
- (c)
- (d)
Answer and solution
Answer (c)
Solution
Chemistry ma’am · 3 steps
Same first-order law as radioactive decay, but with a plus sign: the colony grows exponentially from 1.
- Write the rate law. In radioactive decay the rate is proportional to the number present, so it is first order. Bacteria multiply the same way: the more bacteria there are, the faster new ones form. The only change is that N goes up instead of down, so dN/dt = +kN.
N/N₀ = eᵏᵗ
- Read the shape. At t = 0 the ratio is e⁰ = 1, so the curve starts above the origin. After that it rises ever more steeply, because the slope kN grows as N grows.
Option Shape of the graph Fits N/N₀ = eᵏᵗ? (a) Falls along a curve from a high value No, this is first-order decay (b) Falls along a straight line No, this is zero-order loss (c) Starts at a nonzero value, rises more and more steeply Yes (d) Starts at zero, rises, then levels off No, wrong start and it slows down - So. Only graph (c) shows exponential growth that starts at N/N₀ = 1 and keeps speeding up. The answer is (c).
The idea to keep. Similar to radioactive decay means first order, so the graph is an exponential. Then check the sign: growth curves upwards from N/N₀ = 1, while decay falls from it.
Answer from the NTA final answer key. Solution by PrepWiser.