JEE Main 2021 · 17 March · evening · Numerical answer · +4 / −0

The reaction 2A + B₂ → 2AB is an elementary reaction.
For a certain quantity of reactants, if the volume of the reaction vessel is reduced by a factor of 3, the rate of the reaction increases by a factor of ____________. (Round off to the Nearest Integer).

Answer and solution

Answer 27

Solution

Chemistry ma’am · 3 steps

Elementary means the stoichiometry is the rate law: squeeze to a third and both concentrations triple.

  1. Write the rate law. For an elementary reaction the exponents are the stoichiometric coefficients. So for 2A + B₂ → 2AB the rate is r = k[A]²[B₂], an overall order of 3.
  2. Shrink the volume. The amounts of A and B₂ stay the same, and concentration is moles divided by volume. Cutting the volume to one third makes each concentration 3 times larger.

    r₂/r₁ = k(3[A])²(3[B₂])/k[A]²[B₂] = 3² × 3 = 27

  3. So. The rate increases by a factor of 27.

The common slip: 9. Cubing the factor is easy to miss: using order 1 gives 3, and using only the [A]² term gives 9, not 27.

The idea to keep. When the volume changes by a factor, every concentration changes by that factor, so the rate changes by the factor raised to the overall order.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Chemical Kinetics

Asked about 150 times in JEE Main since 2020. This question is from 2021.