JEE Main 2021 · 26 August · morning · Single correct · +4 / −1

Statement I : By doping silicon semiconductor with pentavalent material, the electrons density increases.
Statement II : The n-type semiconductor has net negative charge.
In the light of the above statements, choose the most appropriate answer from the options given below :

  1. (a) Statement - I is true but Statement - II is false.
  2. (b) Statement - I is false but Statement - II is true.
  3. (c) Both Statement I and Statement II are true.
  4. (d) Both Statement I and Statement II are false.
Answer and solution

Answer (a) Statement - I is true but Statement - II is false.

Solution

Physics sir · 4 steps

Doping adds electrons, but every electron leaves a positive ion behind, so the crystal stays neutral.

  1. Statement I. A pentavalent atom such as P or As has 5 valence electrons. Four of them bond with neighbouring Si atoms and the fifth is loosely held, so it becomes a free electron at room temperature. The electron density rises, so Statement I is true.
  2. Count the charges. Each donor atom that gives away its extra electron becomes a fixed positive ion, P⁺. So every extra free electron is matched by one positive donor ion in the lattice.

    nₑ = nₕ + N_D⁺

  3. Statement II. Total negative charge (electrons) equals total positive charge (holes plus donor ions). The n-type crystal is electrically neutral, so Statement II is false. The "n" tells you the majority carriers are electrons, not that the crystal carries a net negative charge.
  4. So. Statement I is true and Statement II is false, which is option (a).

The idea to keep. Doping never adds net charge, because you are adding neutral atoms. n-type and p-type only name the majority carrier; both crystals stay electrically neutral.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Semiconductors & Electronic Devices

Asked about 170 times in JEE Main since 2020. This question is from 2021.