JEE Main 2021 · 25 February · evening · Single correct · +4 / −1

For extrinsic semiconductors; when doping level is increased;

  1. (a) Fermi-level of both p-type and n-type semiconductors will go upward for T > T F K and downward for T < T F K, where T F is Fermi temperature.
  2. (b) Fermi-level of p-type semiconductor will go upward and Fermi-level of n-type semiconductors will go downward
  3. (c) Fermi-level of p and n-type semiconductors will not be affected.
  4. (d) Fermi-level of p-type semiconductors will go downward and Fermi-level of n-type semiconductor will go upward.
Answer and solution

Answer (d) Fermi-level of p-type semiconductors will go downward and Fermi-level of…

Solution

Physics sir · 4 steps

Fermi level follows the majority carriers: more holes pull it down, more electrons push it up.

  1. Intrinsic start. In a pure semiconductor the Fermi level sits near the middle of the band gap, because electrons and holes are equal in number.
  2. n-type doping. Donor atoms add electrons near the conduction band. More donors mean more electrons in the conduction band, so the Fermi level moves upward, towards the conduction band.
  3. p-type doping. Acceptor atoms create holes near the valence band. More acceptors mean more holes, so the Fermi level moves downward, towards the valence band.
  4. So. Raising the doping level lowers the Fermi level in p-type and raises it in n-type, which is option (d).

The idea to keep. The Fermi level always shifts towards the band holding the majority carriers. Heavier doping means a bigger shift: up to the conduction band for n-type, down to the valence band for p-type.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 170 times in JEE Main since 2020. This question is from 2021.