JEE Main 2021 · 26 February · evening · Single correct · +4 / −1

A particle executes S.H.M., the graph of velocity as a function of displacement is :

  1. (a) a parabola
  2. (b) a helix
  3. (c) an ellipse
  4. (d) a circle
Answer and solution

Answer (c) an ellipse

Solution

Physics sir · 4 steps

Write v in terms of x, square it, and the ellipse equation appears right in front of you.

  1. Velocity in SHM. For SHM with amplitude A and angular frequency ω, the speed at displacement x is v = ω√(A² - x²).
  2. Square and rearrange. Squaring gives v² = ω² (A² - x²). Divide every term by ω² A² and move the x² term to the left.

    x²/A² + v²/(ω² A²) = 1

  3. Read the shape. This is x²/a² + y²/b² = 1 with semi-axes a = A along x and b = ω A along v. Since ω A is in general not equal to A, the curve is an ellipse.
  4. So. The velocity versus displacement graph is an ellipse, option (c).

The idea to keep. In SHM, x and v always satisfy x²/A² + v²/(ω² A²) = 1. So v against x is an ellipse, while a against x is a straight line through the origin.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Simple Harmonic Motion

Asked about 130 times in JEE Main since 2020. This question is from 2021.