JEE Main 2024 · 1 February · morning · Single correct · +4 / −1

The reading in the ideal voltmeter (V) shown in the given circuit diagram is :

JEE Main PYQ figure
  1. (a) 3 V
  2. (b) 10 V
  3. (c) 5 V
  4. (d) 0 V
Answer and solution

Answer (d) 0 V

Solution

Physics sir · 3 steps

Eight identical cells in one loop: find the current, then the drop inside each cell eats its whole EMF.

  1. Count the loop. There are 8 identical cells, 3 on top, 3 at the bottom, 1 on the left and 1 on the right. Each is 5 V with internal resistance 0.2 Ω, all in series and aiding each other. The ideal voltmeter draws no current, so it does not change the loop.
  2. Loop current. Total EMF is 8 × 5 = 40 V and total resistance is 8 × 0.2 = 1.6 Ω. So I = 40/1.6 = 25 A.

    V = E - Ir = 5 - 25 × 0.2 = 0 V

  3. So. The voltmeter sits across the right-hand cell, and that cell's terminal voltage is zero. The reading is 0 V, option (d).

The idea to keep. A voltmeter across a cell reads the terminal voltage E - Ir, not the EMF. When identical cells are shorted in a ring, Ir = E for every cell, so every terminal voltage is zero.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Current Electricity

Asked about 250 times in JEE Main since 2020. This question is from 2024.