JEE Main 2023 · 29 January · morning · Numerical answer · +4 / −0

Millimoles of calcium hydroxide required to produce 100 mL of the aqueous solution of pH 12 is x×10⁻¹. The value of x is ___________ (Nearest integer).
Assume complete dissociation.

Answer and solution

Answer 5

Solution

Chemistry ma’am · 4 steps

Go from pH to hydroxide, then remember each calcium hydroxide gives two hydroxide ions.

  1. Find the hydroxide. At 25 °C, pH + pOH = 14, so pH 12 means pOH 2. That gives [OH⁻] = 10⁻² M.
  2. Millimoles of hydroxide. Millimoles = molarity × volume in mL = 10⁻² × 100 = 1 millimole of OH⁻.

    Ca(OH)₂ → Ca²⁺ + 2OH⁻

  3. Two hydroxides each. Each Ca(OH)₂ releases two OH⁻ ions, so you need half as much base: 1/2 = 0.5 millimole = 5 × 10⁻¹ millimole.
  4. So. x = 5.

The common slip: 10. Forgetting that one Ca(OH)₂ gives two OH⁻ leaves the answer at 1 millimole, which is 10 × 10⁻¹ and gives 10, not 5.

The idea to keep. For a base, pH gives you [OH⁻] through pOH, not the base concentration itself. Divide by the number of OH⁻ each formula unit releases.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Ionic Equilibrium

Asked about 100 times in JEE Main since 2020. This question is from 2023.