JEE Main 2022 · 25 June · morning · Single correct · +4 / −1

The height of any point P above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point P will be : (Given g = acceleration due to gravity at the surface of earth).

  1. (a) g/2
  2. (b) g/4
  3. (c) g/3
  4. (d) g/9
Answer and solution

Answer (d) g/9

Solution

Physics sir · 3 steps

Measure distance from the centre of the earth, not from the surface: P is at 3R, not 2R.

  1. Distance from centre. The height is the diameter, so h = 2R. Gravity depends on the distance from the earth's centre, which is r = R + h = 3R.

    g' = GM/(R+h)² = g(R/(R+h))²

  2. Put in numbers. g' = g(R/3R)² = g × 1/9.
  3. So. The acceleration due to gravity at P is g/9, option (d).

The idea to keep. Above the surface, g falls as 1/r² with r measured from the earth's centre. Always add R to the height before you square.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Gravitation

Asked about 160 times in JEE Main since 2020. This question is from 2022.