JEE Main 2022 · 30 June · morning · Single correct · +4 / −1

For a solution of the gases A, B, C and D in water at 298 K, the values of Henry's law constant (K H ) are 30.40, 2.34, 1.56 × 10⁻⁵ and 0.513 k bar respectively. In the given graph, the lines marked as 'p' and 's' correspond respectively to :

JEE Main PYQ figure
  1. (a) A and C
  2. (b) B and A
  3. (c) D and A
  4. (d) C and D
Answer and solution

Answer (a) A and C

Solution

Chemistry ma’am · 3 steps

In Henry's law, K_H sets the height of the line: the biggest K_H sits on top, the smallest at the bottom.

  1. Henry's law. The partial pressure of a gas over its solution is p = K_H x_(gas), and in a two-component solution x_(gas) = 1 - x_(H₂O).

    p = K_H(1 - x_(H₂O))

  2. Read the graph. At any fixed x_(H₂O), a gas with a larger K_H shows a higher partial pressure, and its line also falls more steeply. So the top line has the largest K_H, and the nearly flat bottom line has the smallest K_H.
    GasK_H (kbar)RankLine
    A30.40largestp (top)
    B2.34secondq
    D0.513thirdr
    C1.56 × 10⁻⁵smallests (flat, bottom)
  3. So. Line p belongs to A and line s belongs to C, which is option (a).

The idea to keep. A larger K_H means a higher partial pressure for the same composition, so the gas is less soluble. On a p vs mole fraction graph, rank the lines by K_H from top to bottom.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 150 times in JEE Main since 2020. This question is from 2022.