JEE Main 2025 · 3 April · evening · Single correct · +4 / −1

Let the equation x(x+2)(12-k)=2 have equal roots. Then the distance of the point (k, k/2) from the line 3 x+4 y+5=0 is

  1. (a) 15
  2. (b) 12
  3. (c) 5 √3
  4. (d) 15 √5
Answer and solution

Answer (a) 15

Solution

Maths sir · 4 steps

Equal roots means the discriminant is zero. That gives k, and then it is a plain distance formula.

  1. Make it quadratic. Expand and move 2 across to get (12-k)x² + 2(12-k)x - 2 = 0. For equal roots this must be a genuine quadratic with discriminant zero.

    4(12-k)² + 8(12-k) = 4(12-k)(14-k) = 0

  2. Pick the right k. k = 12 kills the x² term and leaves -2 = 0, which has no roots at all. So k = 14, and the point is (14, 7).
  3. Distance formula. Distance = (|3(14) + 4(7) + 5|)/√(3² + 4²) = (|42 + 28 + 5|)/5 = 75/5.
  4. So. The distance is 15, option (a).

The idea to keep. Equal roots means discriminant zero, but always check that the leading coefficient is not zero. A value of k that removes the x² term must be rejected.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Straight Lines

Asked about 130 times in JEE Main since 2020. This question is from 2025.