JEE Main 2024 · 8 April · evening · Single correct · +4 / −1

If the image of the point (-4,5) in the line x+2 y=2 lies on the circle (x+4)²+(y-3)²=r², then r is equal to:

  1. (a) 2
  2. (b) 3
  3. (c) 4
  4. (d) 1
Answer and solution

Answer (a) 2

Solution

Maths sir · 4 steps

Find the mirror image with the reflection formula, then measure its distance to the circle's centre.

  1. Reflection formula. For the line ax + by + c = 0, the image (h, k) of a point (x₁, y₁) satisfies the relation below. Here the line is x + 2y - 2 = 0, so a = 1, b = 2, c = -2.

    (h - x₁)/a = (k - y₁)/b = -2(a x₁ + b y₁ + c)/(a² + b²)

  2. Find the image. Put in (-4, 5): ax₁ + by₁ + c = -4 + 10 - 2 = 4 and a² + b² = 5, so the common ratio is -8/5. Then h = -4 - 8/5 = -28/5 and k = 5 - 16/5 = 9/5.
  3. Distance to centre. The circle has centre (-4, 3), and the image lies on the circle, so r is the distance from the image to the centre. That gives h + 4 = -8/5, k - 3 = -6/5, and r² = 64/25 + 36/25 = 4.
  4. So. r = 2, which is option (a).

The idea to keep. For the image in a line, use (h-x₁)/a=(k-y₁)/b=-2(ax₁+by₁+c)/(a²+b²). Keep the -2; using -1 gives the foot of the perpendicular instead.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Straight Lines

Asked about 130 times in JEE Main since 2020. This question is from 2024.