JEE Main 2024 · 5 April · morning · Single correct · +4 / −1

The angle between vector Q⃗ and the resultant of (2Q⃗+2P⃗) and (2Q⃗-2P⃗) is :

  1. (a) tan⁻¹(P/Q)
  2. (b) 0°
  3. (c) tan⁻¹(2Q⃗-2P⃗)/(2Q⃗+2P⃗)
  4. (d) tan⁻¹(2Q/P)
Answer and solution

Answer (b) 0°

Solution

Physics sir · 3 steps

Add the two vectors first: the P⃗ parts cancel, and whatever is left points exactly along Q⃗.

  1. Add the vectors. The resultant is the vector sum of the two given vectors. Add them term by term.

    R⃗ = (2Q⃗ + 2P⃗) + (2Q⃗ - 2P⃗) = 4Q⃗

  2. Read the direction. +2P⃗ and -2P⃗ cancel exactly, so R⃗ = 4Q⃗. Multiplying a vector by a positive number changes only its length, not its direction.
  3. So. R⃗ points along Q⃗, so the angle between them is 0°, option (b).

The idea to keep. Before you reach for tan⁻¹ formulas, add the vectors algebraically. If the result is a positive multiple of a vector, it is parallel to it and the angle is zero.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Vectors

Asked about 40 times in JEE Main since 2020. This question is from 2024.