A light whose electric field vectors are completely removed by using a good polaroid, allowed to incident on the surface of the prism at Brewster's angle. Choose the most suitable option for the phenomenon related to the prism.

Solution

Physics sir · 4 steps

At Brewster's angle, light vibrating in the plane of incidence cannot reflect, so all of it goes in.

1. What reaches the prism. A polaroid lets through only one direction of vibration. Here it has removed the component perpendicular to the plane of incidence, so the light reaching the prism vibrates only in the plane of incidence.
2. Brewster condition. At Brewster's angle i_B, the reflected and refracted directions would be at 90° to each other.

   tan i_B = μ, i_B + r = 90°

3. Why nothing reflects. Reflected light is re-radiated by electrons in the glass, which vibrate along the electric field of the refracted wave. For the in-plane component, that vibration points exactly along the reflected direction, and a vibrating charge does not radiate along its own line of vibration. So the in-plane component has zero reflection at i_B.
4. So. Only in-plane light arrives, and none of it can reflect. There is no reflected ray, and all the light is transmitted into the prism: option (d).

The idea to keep. At Brewster's angle the reflected light is fully polarised perpendicular to the plane of incidence. If the incoming light has only the in-plane vibration, there is nothing to reflect and it is all transmitted.

Answer from the NTA final answer key. Solution by PrepWiser.