JEE Main 2024 · 30 January · evening · Single correct · +4 / −1
A beam of unpolarised light of intensity I₀ is passed through a polaroid A and then through another polaroid B which is oriented so that its principal plane makes an angle of 45° relative to that of A. The intensity of emergent light is:
- (a) I₀ / 2
- (b) I₀ / 8
- (c) I₀ / 4
- (d) I₀
Answer and solution
Answer (c) I₀ / 4
Solution
Physics sir · 3 steps
Two stages here: the first polaroid halves the light, then Malus' law handles the 45° tilt.
- Through polaroid A. Unpolarised light vibrates in every direction equally, so a polaroid passes the average of cos² θ over all angles, which is 1/2. The light leaving A has intensity I₀/2 and is now polarised along A's axis.
- Through polaroid B. This light is already polarised, so Malus' law applies with θ = 45° between the two axes.
I = I₀/2 cos² 45° = I₀/2 × 1/2 = I₀/4
- So. The emergent intensity is I₀/4, option (c).
The idea to keep. For unpolarised light, the first polaroid always gives half the intensity, whatever its angle. Use Malus' law I = I'cos² θ only from the second polaroid onwards.
Answer from the NTA final answer key. Solution by PrepWiser.