JEE Main 2025 · 7 April · evening · Single correct · +4 / −1
Match List - I with List - II .
Choose the correct answer from the options given below :
| List - I | List - II |
|---|---|
| (A) Solution of chloroform and acetone | (I) Minimum boiling azeotrope |
| (B) Solution of ethanol and water | (II) Dimerizes |
| (C) Solution of benzene and toluene | (III) Maximum boiling azeotrope |
| (D) Solution of acetic acid in benzene | (IV) ΔVₘᵢₓ = 0 |
- (a) (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- (b) (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- (c) (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
- (d) (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
Answer and solution
Answer (a) (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
Solution
Chemistry ma’am · 4 steps
Ask what each pair does to the forces between molecules, and every match falls into place.
- Negative deviation. In chloroform and acetone, the H of CHCl₃ hydrogen-bonds to the C=O oxygen of acetone. The A–B attraction is stronger than A–A or B–B, so vapour pressure drops below Raoult's law and the mixture forms a maximum boiling azeotrope.
- Positive deviation. Ethanol breaks into water's hydrogen-bond network, so A–B attraction is weaker than in the pure liquids. Vapour pressure rises above Raoult's law, giving a minimum boiling azeotrope (about 95% ethanol).
- Ideal and dimer. Benzene and toluene are so alike that the mixture is nearly ideal, so Δ Vₘᵢₓ = 0. Acetic acid in benzene pairs up through two hydrogen bonds and dimerizes.
Solution Behaviour Match (A) chloroform + acetone negative deviation (III) maximum boiling azeotrope (B) ethanol + water positive deviation (I) minimum boiling azeotrope (C) benzene + toluene nearly ideal (IV) Δ Vₘᵢₓ = 0 (D) acetic acid in benzene association (II) dimerizes - So. The matching is (A)-(III), (B)-(I), (C)-(IV), (D)-(II), which is option (a).
The idea to keep. Stronger A–B attraction means lower vapour pressure and a maximum boiling azeotrope. Weaker A–B attraction means higher vapour pressure and a minimum boiling azeotrope.
Answer from the NTA final answer key. Solution by PrepWiser.