JEE Main 2025 · 2 April · evening · Single correct · +4 / −1

The nature of oxide (TeO₂) and hydride (TeH₂) formed by Te , respectively are :

  1. (a) Reducing and basic
  2. (b) Reducing and acidic
  3. (c) Oxidising and acidic
  4. (d) Oxidising and basic
Answer and solution

Answer (c) Oxidising and acidic

Solution

Chemistry ma’am · 3 steps

Go down group 16: the dioxides lose reducing power and the hydrides gain acidic strength.

  1. The dioxide. In EO₂ the element is in the +4 state. Going down the group, the +4 state becomes more stable and the +6 state less stable. So SO₂ is a reducing agent, but TeO₂ acts as an oxidising agent.
  2. The hydride. Acidic character of the hydrides goes H₂O < H₂S < H₂Se < H₂Te. The Te atom is large, so the H–Te bond is long and weak, and H₂Te gives up H⁺ most easily. It is the most acidic hydride of the family.
    ElementDioxide behaves asHydride is
    SSO₂: reducingH₂S: weakly acidic
    SeSeO₂: oxidisingH₂Se: more acidic
    TeTeO₂: oxidisingH₂Te: most acidic
  3. So. TeO₂ is oxidising and H₂Te is acidic, which is option (c).

The idea to keep. Down group 16, the +4 state gets more stable, so the dioxides turn from reducing to oxidising. The E–H bond gets weaker, so the hydrides get more acidic.

Answer from the NTA final answer key. Solution by PrepWiser.

Study p-Block Elements — Part II (Group 15-18)

Asked about 110 times in JEE Main since 2020. This question is from 2025.