JEE Main 2020 · 7 January · morning · Single correct · +4 / −1
Oxidation number of potassium in K₂O. K₂O₂ and KO₂ respectively is :
- (a) +1, +2 and + 4
- (b) +1, +1 and + 1
- (c) +2, +1 and + 1/2
- (d) +1, +4, and +2
Answer and solution
Answer (b) +1, +1 and + 1
Solution
Chemistry ma’am · 3 steps
Fix potassium first: a Group 1 metal is always +1, so let oxygen take whatever value is left.
- Start with potassium. Potassium is an alkali metal with one valence electron, and it always loses that electron in its compounds. So K is +1 in every one of these. Oxygen is the element whose oxidation number changes here.
Compound Oxygen species Oxidation number of O Oxidation number of K K₂O (oxide) O²⁻ -2 2x - 2 = 0, so x = +1 K₂O₂ (peroxide) O₂²⁻ -1 2x - 2 = 0, so x = +1 KO₂ (superoxide) O₂⁻ -1/2 x - 1 = 0, so x = +1 - Why oxygen changes. In a peroxide the two O atoms share a charge of -2, so each is -1. In a superoxide the two O atoms share only -1, so each is -1/2. The total charge on the oxygen part always matches the number of K atoms.
- So. Potassium is +1, +1 and +1 in the three compounds, which is option (b).
The idea to keep. Alkali metals are always +1 and alkaline earth metals always +2 in their compounds. In oxides, peroxides and superoxides, oxygen is the one that changes: -2, -1 and -1/2.
Answer from the NTA final answer key. Solution by PrepWiser.