JEE Main 2023 · 11 April · morning · Single correct · +4 / −1
As per the given graph, choose the correct representation for curve A and curve B.
Where X_C= reactance of pure capacitive circuit connected with A.C. source
X_L= reactance of pure inductive circuit connected with A . C. source
R = impedance of pure resistive circuit connected with A.C. source.
Z= Impedance of the LCR series circuit }
- (a) A=X_L, B=R
- (b) A=X_L, B=Z
- (c) A=X_C, B=X_L
- (d) A=X_C, B=R
Answer and solution
Answer (c) A=X_C, B=X_L
Solution
Physics sir · 3 steps
Ask how each quantity depends on f: one falls as 1/f, one rises in a straight line from zero.
- Read the curves. Curve A starts very high and falls towards zero as f grows, like a hyperbola. Curve B is a straight line through the origin, so it is directly proportional to f.
Quantity Formula How it varies with f Shape on the graph X_C 1/(2π f C) ∝ 1/f falling hyperbola (curve A) X_L 2π f L ∝ f straight line through origin (curve B) R R independent of f horizontal line Z √(R² + (X_L - X_C)²) falls, then rises U-shape, minimum R at resonance - Match the shapes. Only X_C falls as 1/f, so it is curve A. Only X_L grows in direct proportion to f starting from zero, so it is curve B.
- So. Curve A is X_C and curve B is X_L, which is option (c).
The idea to keep. Remember the four shapes against frequency: X_L is a rising straight line, X_C is a falling hyperbola, R is flat, and Z is a U with its lowest point R at resonance.
Answer from the NTA final answer key. Solution by PrepWiser.