JEE Main 2024 · 1 February · morning · Numerical answer · +4 / −1
The potential for the given half cell at 298 K is (-) __________ × 10⁻² V
2 H_((aq))⁺+2 e⁻ → H₂( g) ; ; [H⁺]=1 M, P_(H₂)=2 atm
(Given : 2.303 RT / F=0.06 V, log 2=0.3 )
Answer and solution
Answer 1
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