JEE Main 2024 · 4 April · evening · Single correct · +4 / −1

When MnO₂ and H₂ SO₄ is added to a salt (A), the greenish yellow gas liberated as salt (A) is :

  1. (a) NH₄ Cl
  2. (b) CaI₂
  3. (c) KNO₃
  4. (d) NaBr
Answer and solution

Answer (a) NH₄ Cl

Solution

Chemistry ma’am · 3 steps

Greenish yellow gas means chlorine, so look for the salt that carries a chloride ion.

  1. Name the gas. Chlorine is the only common gas in salt analysis that is greenish yellow. So salt (A) must contain the Cl⁻ ion.
  2. What MnO2 does. Concentrated H₂SO₄ supplies the acid, and MnO₂ acts as an oxidising agent. It oxidises a halide ion to the free halogen, and each halogen has its own colour.

    MnO₂ + 4H⁺ + 2Cl⁻ → Mn²⁺ + 2H₂O + Cl₂ ↑

    SaltAnionGas or vapour releasedColour
    NH₄ClCl⁻Cl₂greenish yellow
    CaI₂I⁻I₂ vapourviolet
    KNO₃NO₃⁻no halogen; with conc. H₂SO₄ on heating, NO₂light brown
    NaBrBr⁻Br₂ vapourreddish brown
  3. So. Only NH₄Cl gives chlorine: 2NH₄Cl + MnO₂ + 2H₂SO₄ → (NH₄)₂SO₄ + MnSO₄ + 2H₂O + Cl₂. Salt (A) is option (a).

The idea to keep. With MnO₂ and conc. H₂SO₄, the halide shows its colour: chloride gives greenish yellow Cl₂, bromide gives reddish brown Br₂, iodide gives violet I₂.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Qualitative Analysis — Salt Analysis

Asked about 80 times in JEE Main since 2020. This question is from 2024.