In the given figure the total charge stored in the combination of capacitors is 100 μ C. The value of ' x ' is _________.

Solution

Physics sir · 4 steps

All three capacitors sit across the same two wires, so they are in parallel and their capacitances just add.

1. Spot the connection. Each capacitor joins the left wire to the right wire. So all three have the same 10 V across them, which means they are in parallel.
2. Equivalent capacitance. In parallel, capacitances add: C_(eq) = 2 + x + 3 = (5 + x) μF.

   Q = C_(eq)V ⇒ 100 μC = (5 + x) μF × 10 V

3. Solve for x. 5 + x = 100/10 = 10, so x = 5.
4. So. The value of x is 5, that is, C₂ = 5 μF.

The idea to keep. Before using any formula, trace where each capacitor's plates connect. Same two nodes means parallel: the voltage is shared, capacitances add, and the charges add to give the total.

Answer from the NTA final answer key. Solution by PrepWiser.