JEE Main 2023 · 10 April · morning · Single correct · +4 / −1

A particle of mass m moving with velocity v collides with a stationary particle of mass 2m. After collision, they stick together and continue to move together with velocity

  1. (a) v
  2. (b) v/3
  3. (c) v/4
  4. (d) v/2
Answer and solution

Answer (b) v/3

Solution

Physics sir · 3 steps

They stick together, so total momentum stays put while the mass triples: the speed must drop to a third.

  1. Momentum is conserved. No external force acts during the collision, so total momentum before equals total momentum after. Kinetic energy is not conserved here, because the particles stick together.

    m v + 2m × 0 = (m + 2m) V

  2. Solve for V. The left side is mv and the combined mass is 3m. So mv = 3mV, which gives V = v/3.
  3. So. The two particles move together with velocity v/3, option (b).

The idea to keep. In a perfectly inelastic collision, use momentum only: common velocity = total momentum divided by total mass. Never use kinetic energy, because it is lost when bodies stick.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Collision

Asked about 40 times in JEE Main since 2020. This question is from 2023.