JEE Main 2024 · 6 April · evening · Single correct · +4 / −1

Evaluate the following statements related to group 14 elements for their correctness.
(A) Covalent radius decreases down the group from C to Pb in a regular manner.
(B) Electronegativity decreases from C to Pb down the group gradually.
(C) Maximum covalance of C is 4 whereas other elements can expand their covalance due to presence of d orbitals.
(D) Heavier elements do not form p π-p π bonds.
(E) Carbon can exhibit negative oxidation states.
Choose the correct answer from the options given below :

  1. (a) (A), (B) and (C) Only
  2. (b) (A) and (B) Only
  3. (c) (C), (D) and (E) Only
  4. (d) (C) and (D) Only
Answer and solution

Answer (c) (C), (D) and (E) Only

Solution

Chemistry ma’am · 3 steps

Test each claim against the real data: radius goes up, and electronegativity barely moves after silicon.

  1. Trend statements. (A) and (B) describe smooth trends down the group. Check them against the actual values before you accept them. The table uses the textbook values.
    StatementWhat the data or chemistry saysVerdict
    (A) Covalent radius decreasesC 77, Si 118, Ge 122, Sn 140, Pb 146 pm. It increases down the group, and not by equal amounts.False
    (B) Electronegativity falls graduallyC 2.5, then Si, Ge and Sn are all 1.8, and Pb is 1.9. There is one big drop, then almost no change.False
    (C) C limited to covalency 4C has only 2s and 2p orbitals. Si onwards use d orbitals, as in [SiF₆]²⁻.True
    (D) No pπ - pπ bonds for heavier elementsLarge atoms give poor sideways overlap of p orbitals. Only C forms stable C=C and C≡C bonds.True
    (E) Negative oxidation states for CC is more electronegative than H and metals. It shows -4 in CH₄ and in carbides such as Al₄C₃.True
  2. Why C is different. Carbon is small, highly electronegative and has no d orbitals. That one fact explains why (C), (D) and (E) are all true.
  3. So. (A) and (B) are false, and (C), (D) and (E) are correct, which is option (c).

The idea to keep. Down group 14, radius increases with a big jump from C to Si. Electronegativity drops sharply from C to Si and then stays almost flat. Carbon's small size and lack of d orbitals make it the odd one out.

Answer from the NTA final answer key. Solution by PrepWiser.

Study p-Block Elements — Part I (Group 13 & 14)

Asked about 60 times in JEE Main since 2020. This question is from 2024.