JEE Main 2024 · 27 January · morning · Single correct · +4 / −1
If the refractive index of the material of a prism is cot (A/2), where A is the angle of prism then the angle of minimum deviation will be
- (a) π-2 A
- (b) π/2-2 A
- (c) π-A
- (d) π/2-A
Answer and solution
Answer (a) π-2 A
Solution
Physics sir · 4 steps
Write cot as cos over sin, and the prism formula hands you a sine you can match directly.
- Prism formula. At minimum deviation δₘ, the refractive index of a prism with angle A is given by the relation below.
μ = sin((A+δₘ)/2)/sin(A/2) = cot(A/2) = cos(A/2)/sin(A/2)
- Match the numerators. The denominators are the same, so sin((A+δₘ)/2) = cos(A/2) = sin(π/2 - A/2).
- Solve for deviation. So (A+δₘ)/2 = π/2 - A/2. Multiply by 2 to get A + δₘ = π - A.
- So. δₘ = π - 2A, which is option (a).
The idea to keep. When μ is given as a trig function of A, put it into μ = sin(A+δₘ)/2 / sin A/2 and use cos θ = sin(π/2-θ) to compare the angles.
Answer from the NTA final answer key. Solution by PrepWiser.