JEE Main 2023 · 13 April · morning · Numerical answer · +4 / −0
A₂+B₂ → 2 AB . Δ H_f⁰=-200 kJ mol⁻¹
AB, A₂ and B₂ are diatomic molecules. If the bond enthalpies of A₂, B₂ and AB are in the ratio 1: 0.5: 1, then the bond enthalpy of A₂ is ____________ kJ mol⁻¹ (Nearest integer)
Answer and solution
Answer 400
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