JEE Main 2023 · 8 April · evening · Single correct · +4 / −1

Let S be the set of all values of θ ∈[-π, π] for which the system of linear equations
x+y+√3 z=0
-x+(tan θ) y+√7 z=0
x+y+(tan θ) z=0
has non-trivial solution. Then 120/π Σθ ∈ s θ is equal to :

  1. (a) 40
  2. (b) 30
  3. (c) 10
  4. (d) 20
Answer and solution

Answer (d) 20

Solution

Maths sir · 4 steps

Non-trivial solution means the determinant is zero. Factor it, then collect every angle in [-π, π].

  1. Set determinant zero. A homogeneous system has a non-trivial solution only when its coefficient determinant is 0. Write t = tan θ and subtract row 1 from row 3, so row 3 becomes (0, 0, t-√3).

    |1, 1, √3; -1, t, √7; 0, 0, t-√3| = (t-√3)(t+1) = 0

  2. Find every angle. tan θ = √3 gives θ = π/3, -2π/3. tan θ = -1 gives θ = -π/4, 3π/4. Each value of tan repeats every π, so it has two angles in [-π, π].
  3. Add them. π/3 - 2π/3 - π/4 + 3π/4 = -π/3 + π/2 = π/6.
  4. So. 120/π × π/6 = 20, which is option (d).

The idea to keep. Homogeneous system with a non-trivial solution means determinant = 0. When the answer is a trig equation on an interval, list every solution in that interval, not only the principal value.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Determinants

Asked about 190 times in JEE Main since 2020. This question is from 2023.